April Fool's Day Problem of the DayApr 01, 2020
April Fool’s Day Problem of the Day
Today we are going to take a short break for the typical problem of the day. The first of the April Fool’s Day problems is appropriate for all age groups. The second will test your knowledge of Algebra so is best left to 8th graders and above. I hope you enjoy these brain teaser math tricks.
Write down a three digit number. The first and third digits must differ by more than 1. 735
Reverse the digits to form a second number. 537
Now subtract the smaller number from the larger. 735 - 537 = 198
Now reverse the digits in the answer you got in step three and add it to that number. 198 + 891 = 1089
Multiply the number by 1 million 1089 X 1,000,000 = 1,089,000,000
Subtract 733,361,573 from that number
1,089,000,000 - 733,361,573 = 355,638,427
Under each of the digits in your answer, write the letter which corresponds to it using the following table:
Now read your message backwards!
Find which step in the following proof creates the fallacy.
Step 8 2 = 1
Problem 1 - April Fool
Problem 2 - Step 8 creates the fallacy because you are dividing both sides by which means it cannot be equal to zero but in Step 1 you said a = b so must equal zero.
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